java - Regex to extract lines after the last occurence -

hi have paragraph :

            output 123              deepak everywhere             deepak              output 123              ankur everywhere             deepak              last              deepak everywhere             deepak 

i want extract after last occurrence of "output 123" "last" . expect :

            ankur everywhere             deepak              last 

i use regex pattern - (?<=(output))([^\\n]*)last . using this, :

            output 123              deepak everywhere             deepak              output 123              ankur everywhere             deepak              last 

can ? use tool - http://regexr.com?360ek

you can use pattern , extract first capturing group:

output\\b[^\\n]*\\s*((?>[^o\\s]++|\\s++(?!last\\b)|o(?!utput\\b))++)(?=\\s+last\b) 

details:

output\\b[^\\n]*\\s* # begining (exclude final result                      # used anchor) (                         # open capturing group     (?>                   # open atomic group (all possible content)         [^o\\s]++         # not "o" or white character       |                   # or         \\s++(?!last\\b)  # white characters not followed "last"                           # (here possessive quantifier needed forbid                           # backtracks)       |                   # or         o(?!utput\\b)     # "o" not followed "utput\b"     )++                   # repeat atomic group 1 or more times )                         # close capturing group (?=\\s+last\b)            # followed white characters , "last" 

you can find content of capturing group with: m.group(1)