oracle - remove rows from table having full outer join condition -

i have used full outer join condition in joining query joining 2 tables , sample code below

  select * from(    select to_char(round(col11)) today1,to_char(round(col12)) today2 t1    full outer join     select to_char(round(col21)) yes1,to_char(round(col22)) yes2 t2   ) main    main.today1<>0 , main.today2<>0 , main.yes1<>0 , main.yes2<>0 

sample output expected below

  today1         today2         yes1            yes2   somevalue     somevalue      null             null    null          null            value       somevalue   somevalue     somevalue       somevalue        value      0                0               0                0 

i trying remove rows having zero values using above clause output doubles , row 0 values apperas. can know going wrong. appreciated.

trying remove rows having 0 values

use:

and not ( main.today1=0 , main.today2=0 , main.yes1=0 , main.yes2=0 ) 

which can transformed, using de morgan's laws:
===> https://en.wikipedia.org/wiki/de_morgan%27s_laws
into:

and ( not main.today1=0 or not main.today2=0 or not main.yes1=0 or not main.yes2=0 ) 

which can further simplified to:

and ( main.today1<>0 or main.today2<>0 or  main.yes1<>0 or main.yes2<>0 ) 

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note: if want null values, must use is null operator:

where ( main.today1<>0 or main.today1 null )   , ( main.today2<>0 or main.today2 null )   , ( main.yes1<>0 or main.yes1 null )   , ( main.yes2<>0 or main.yes2 null )