python - Python3 taking function name as parameter and call it with parameter -

i need take name of function want call parameter list. achieved code (the result b. if liste[0] result a, works.):

def a():     print("aaaa")     return none def b():     print("bbbb")     return none liste = ['a','b'] inputmethodname =  liste[1] locals()[inputmethodname]() 

but in example same thing(at least see in way thats why ask question), giving error. code is:

filterpassflag = 1 controllistforfilter = ['firstcharcontroller']  def firstcharcontroller(singleline):     if singleline[0] == "1":         filterpassflag = 0     return none  def startcontrol(singleline):     controllistforfilteriterator  = 0     while (controllistforfilteriterator < len(controllistforfilter)) & (filterpassflag == 1):         inputmethodname = controllistforfilter[controllistforfilteriterator]         locals()[inputmethodname](singleline) #******error in line.         controllistforfilteriterator = controllistforfilteriterator + 1     return none  singleline = "bla bla bla bla" startcontrol(singleline) 

output is:

> traceback (most recent call last):   file > "c:/users/berkays/desktop/phyondeneme/phytontest.py", line 37, in > <module> >     startcontrol(singleline)   file "c:/users/berkays/desktop/phyondeneme/phytontest.py", line 24, in > startcontrol >     locals()[inputmethodname](singleline) keyerror: 'firstcharcontroller' process finished exit code 1 

when delete line contains error (local() line) program working. difference between 2 example?