c++ - How does the Compiler Know Whether to Call the const Overload? -

given string foo, when call:

auto bar = foo.begin(); 

there 2 overloads of string::begin. 1 returns string::iterator , other returns string::const_iterator. how can know type of bar? based on whether foo const or not?

is based on whether foo const or not?

yes

auto meant deducing exact type^*

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how select iterator type using auto variable? indirectly agrees answer.

*_{taken from: how const_iterator using auto?}