javascript - Check to see if Array of Objects have >1 property values that !== undefined -

i have array of objects this:

var array = [   {"name": "one", "value": .33},   {"name": "one", "value": .54},   {"name": "one", "value": undefined},    {"name": "two", "value": .3},   {"name": "two", "value": undefined},   {"name": "two", "value": undefined},    {"name": "three", "value": undefined},   {"name": "three", "value": undefined},   {"name": "three", "value": undefined}, ]; 

and need able see if unique name (one/two/three) has 1 number among it's "value" properties. so, in example answer yes because value properties of "two" are: .3, undefined, undefined.

i have way unique "name" fields array:

function names(a) {   var temp = {};   (var = 0; < a.length; i++)     temp[a[i].name] = true;   var r = [];   (var k in temp)     r.push(k);   return r; }  namearray = names(array); 

but when start loop start confused. writing out i'd think like:

var count = 0; (objects name == i){   if (isnan(value) == false){     count++     if(count > 1) {       return true;     }   } } 

of course, pseudo code , not right direction. appreciated, reading!

you can create object count of values numbers each unique name , check if count of name 1 some , return true/false

var array = [{"name":"one","value":0.33},{"name":"one","value":0.54},{"name":"one"},{"name":"two","value":0.3},{"name":"two"},{"name":"two"},{"name":"three"},{"name":"three"},{"name":"three"}],       obj = {}    array.foreach(function(e) {    if(!obj[e.name]) obj[e.name] = 0;    if(typeof e.value == 'number') obj[e.name]+=1;  });    var result = object.keys(obj).some(e => { return obj[e] == 1});  console.log(result)