Bash: if then match on multiple conditions if all are true -


i'm writing script checks 3 different variables , matches on true. need return true if conditions match. right returning true if 1 or 2 conditions match list of operators. 

if [ -z "$var3" ] || [ "$var1" -ge 10 ] || [ "$var2" != "working" ];     echo "app failed "$var1" check-ins"     exit 2  elif [ -n "$var3" ] || [ "$var1" -le 10 ] || [ "$var2" == "working" ];     echo "$var3" pid active connection "$var2"     exit 0 fi

should replace || && ??

yes, || represents or logical operator, returns true if @ least 1 of operators true. && represents , logical operator, returns true if , if o operators true

if [ -z "$var3" ] && [ "$var1" -ge 10 ] && [ "$var2" != "working" ];     echo "app failed "$var1" check-ins"     exit 2  elif [ -n "$var3" ] && [ "$var1" -le 10 ] && [ "$var2" == "working" ];        echo "$var3" pid active connection "$var2"     exit 0 fi

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